1884 United States presidential election in Vermont

1884 United States presidential election in Vermont

← 1880 November 4, 1884 1888 →
 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 4 0
Popular vote 39,514 17,331
Percentage 66.52% 29.18%

County Results
Blaine
  50-60%
  60-70%
  70-80%
  80-90%


President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Vermont took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Vermont by a margin of 37.34%.

With 66.52% of the popular vote, Vermont would be Blaine's strongest victory in terms of percentage in the popular vote.[1]

  1. ^ "1884 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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