Dyskusja:Reakcja chemiczna

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Addition to the article "Reakcja chemizna"

Галактион (dyskusja) 19:45, 22 paź 2009 (CEST)[odpowiedz]

Zrobione

Michał Sobkowski _dyskusja 08:51, 15 lis 2009 (CET)[odpowiedz]

Thank you. Галактион (dyskusja) 12:47, 15 lis 2009 (CET)[odpowiedz]

Let's prove the following chemical implication

2 C + O₂ → 2 CO ${\displaystyle ~\land }$ 2 CO + O₂ → 2 CO₂ ${\displaystyle ~\Rightarrow }$ C + O₂ → CO₂

Notes

The symbol ${\displaystyle ~\land }$ is identical to [logical] and.

Compare:

I love you, and you love me.

I love you. ${\displaystyle ~\land }$ You love me.

The symbol ${\displaystyle ~\Rightarrow }$ is identical to "is known to imply".

Compare:

[The sentence] "I love you." is known to imply [the sentence] "You are loved.".

[The sentence] "I love you." ${\displaystyle ~\Rightarrow }$ [the sentence] "You are loved.".

I love you. ${\displaystyle ~\Rightarrow }$ You are loved.

The symbol ${\displaystyle ~\Leftrightarrow }$ is identical to "is known to mean".

Compare:

[The sentence] "I love you." is known to mean [the sentence] "You are loved by me.".

[The sentence] "I love you." ${\displaystyle ~\Leftrightarrow }$ [the sentence] "You are loved by me.".

I love you. ${\displaystyle ~\Leftrightarrow }$ You are loved by me.

${\displaystyle ~\triangleleft }$ 2 C + O₂ → 2 CO ${\displaystyle ~\land }$ 2 CO + O₂ → 2 CO₂ ${\displaystyle ~\Rightarrow }$

2 C + O₂ + 2 CO + O₂ → 2 CO + 2 CO₂ ${\displaystyle ~\Leftrightarrow }$

2 C + 2 O₂ + 2 CO → 2 CO + 2 CO₂ ${\displaystyle ~\Leftrightarrow }$

2 C + 2 O₂ + 2 CO − 2 CO → 2 CO + 2 CO₂ − 2 CO ${\displaystyle ~\Leftrightarrow }$

2 C + 2 O₂ + (2 − 2) CO → (2 − 2) CO + 2 CO₂ ${\displaystyle ~\Leftrightarrow }$

2 C + 2 O₂ + 0 CO → 0 CO + 2 CO₂ ${\displaystyle ~\Leftrightarrow }$

2 C + 2 O₂ → 2 CO₂ ${\displaystyle ~\Leftrightarrow }$

1/2 • ( 2 C + 2 O₂ ) → 1/2 • 2 CO₂ ${\displaystyle ~\Leftrightarrow }$

1/2 • 2 C + 1/2 • 2 O₂ → 1/2 • 2 CO₂ ${\displaystyle ~\Leftrightarrow }$

1 C + 1 O₂ → 1 CO₂ ${\displaystyle ~\Leftrightarrow }$

C + O₂ → CO₂ ${\displaystyle ~\triangleright }$

Let's prove the following chemical implication

Zn → Zn²⁺ + 2 e⁻ ${\displaystyle ~\land }$ 2 H⁺ + 2 e⁻ → H₂ ${\displaystyle ~\Rightarrow }$ Zn + 2 H⁺ → Zn²⁺ + H₂

${\displaystyle ~\triangleleft }$ Zn → Zn²⁺ + 2 e⁻ ${\displaystyle ~\land }$ 2 H⁺ + 2 e⁻ → H₂ ${\displaystyle ~\Rightarrow }$

Zn + 2 H⁺ + 2 e⁻ → Zn²⁺ + 2 e⁻ + H₂ ${\displaystyle ~\Leftrightarrow }$

Zn + 2 H⁺ + 2 e⁻ − 2 e⁻ → Zn²⁺ + 2 e⁻ + H₂ − 2 e⁻ ${\displaystyle ~\Leftrightarrow }$

Zn + 2 H⁺ + (2 − 2) e⁻ → Zn²⁺ + (2 − 2) e⁻ + H₂ ${\displaystyle ~\Leftrightarrow }$

Zn + 2 H⁺ + 0 e⁻ → Zn²⁺ + 0 e⁻ + H₂ ${\displaystyle ~\Leftrightarrow }$

Zn + 2 H⁺ → Zn²⁺ + H₂ ${\displaystyle ~\triangleright }$

Let's prove the following chemical implication

Fe²⁺ → Fe³⁺ + e ⁻ ${\displaystyle ~\land }$ NO₃⁻ + 4 H⁺ + 3 e⁻ → NO + 2 H₂O ${\displaystyle ~\Rightarrow }$ 3 Fe²⁺ + NO₃⁻ + 4 H⁺ → 3 Fe³⁺ + NO + 2 H₂O

${\displaystyle ~\triangleleft }$ Fe²⁺ → Fe³⁺ + e⁻ ${\displaystyle ~\land }$ NO₃⁻ + 4 H⁺ + 3 e⁻ → NO + 2 H₂O ${\displaystyle ~\Leftrightarrow }$

3 Fe²⁺ → 3 • ( Fe³⁺ + e⁻ ) ${\displaystyle ~\land }$ NO₃⁻ + 4 H⁺ + 3 e⁻ → NO + 2 H₂O ${\displaystyle ~\Leftrightarrow }$

3 Fe²⁺ → 3 Fe³⁺ + 3 e⁻ ${\displaystyle ~\land }$ NO₃⁻ + 4 H⁺ + 3 e⁻ → NO + 2 H₂O ${\displaystyle ~\Rightarrow }$

3 Fe²⁺ + NO₃⁻ + 4 H⁺ + 3 e⁻ → 3 Fe³⁺ + 3 e⁻ + NO + 2 H₂O ${\displaystyle ~\Leftrightarrow }$

3 Fe²⁺ + NO₃⁻ + 4 H⁺ + 3 e⁻ − 3 e⁻ → 3 Fe³⁺ + 3 e⁻ + NO + 2 H₂O − 3 e⁻ ${\displaystyle ~\Leftrightarrow }$

3 Fe²⁺ + NO₃⁻ + 4 H⁺ + (3 − 3) e⁻ → 3 Fe³⁺ + (3 − 3) e⁻ + NO + 2 H₂O ${\displaystyle ~\Leftrightarrow }$

3 Fe²⁺ + NO₃⁻ → 3 Fe³⁺ + NO + 2 H₂O ${\displaystyle ~\triangleright }$

Let's prove the following chemical implication

S²⁻ → S + 2 e⁻ ${\displaystyle ~\land }$ NO₃⁻ + 4 H⁺ + 3 e⁻ → NO + 2 H₂O ${\displaystyle ~\Rightarrow }$ 3 S²⁻ + 2 NO₃⁻ + 8 H⁺ → 3 S + 2 NO + 4 H₂O

${\displaystyle ~\triangleleft }$ S²⁻ → S + 2 e⁻ ${\displaystyle ~\land }$ NO₃⁻ + 4 H⁺ + 3 e⁻ → NO + 2 H₂O ${\displaystyle ~\Leftrightarrow }$

3 S²⁻ → 3 • ( S + 2 e⁻ ) ${\displaystyle ~\land }$ 2 • ( NO₃⁻ + 4 H⁺ + 3 e⁻ ) → 2 • ( NO + 2 H₂O ) ${\displaystyle ~\Leftrightarrow }$

3 S²⁻ → 3 S + 6 e⁻ ${\displaystyle ~\land }$ 2 NO₃⁻ + 8 H⁺ + 6 e⁻ → 2 NO + 4 H₂O ${\displaystyle ~\Rightarrow }$

3 S²⁻ + 2 NO₃⁻ + 8 H⁺ + 6 e⁻ → 3 S + 6 e⁻ + 2 NO + 4 H₂O ${\displaystyle ~\Leftrightarrow }$

3 S²⁻ + 2 NO₃⁻ + 8 H⁺ + 6 e⁻ − 6 e⁻ → 3 S + 6 e⁻ + 2 NO + 4 H₂O − 6 e⁻ ${\displaystyle ~\Leftrightarrow }$

3 S²⁻ + 2 NO₃⁻ + 8 H⁺ → 3 S + 2 NO + 4 H₂O ${\displaystyle ~\triangleright }$

Галактион (dyskusja) 14:25, 20 lis 2009 (CET)[odpowiedz]