1824 United States presidential election in New York

1824 United States presidential election in New York

← 1820 October 26 – December 2, 1824 1828 →
 
Nominee John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Massachusetts Georgia
Running mate John C. Calhoun Martin Van Buren[1]
Electoral vote 26 5

 
Nominee Henry Clay Andrew Jackson
Party Democratic-Republican Democratic-Republican
Home state Kentucky Tennessee
Running mate Nathan Sanford John C. Calhoun
Electoral vote 4 1

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in New York took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. The state legislature chose 36 representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and 4 different candidates from this party sought the Presidency. New York cast 26 electoral votes for John Quincy Adams, 5 for William H. Crawford, 4 for Henry Clay and 1 for Andrew Jackson. This election marks the last time the New York State Legislature chose the state's electors as opposed to using some form of popular vote method.[2]

  1. ^ While Crawford's official running mate was Nathaniel Macon, all of the New York presidential electors who voted for Crawford cast their vice-presidential votes for Van Buren
  2. ^ Moore, John L., ed. (1985). Congressional Quarterly's Guide to U.S. Elections (2nd ed.). Washington, D.C.: Congressional Quarterly, Inc. pp. 254–56.

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