1864 United States presidential election in New York

1864 United States presidential election in New York

← 1860 November 8, 1864 1868 →
Turnout89.3%[1] Decrease 6.2 pp
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 33 0
Popular vote 368,735 361,986
Percentage 50.46% 49.54%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

The 1864 United States presidential election in New York took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 33 representatives, or electors to the Electoral College, who voted for president and vice president.

New York voted for the National Union candidate, incumbent Republican president Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a bare margin of 0.92%.

Although he lost the state, New York would prove to be McClellan's fourth strongest state after Kentucky, New Jersey, and Delaware.[2]

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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