1973 New York City mayoral election

1973 New York City mayoral election

← 1969 November 6, 1973 1977 →
 
Candidate Abraham Beame John J. Marchi
Party Democratic Republican
Popular vote 963,542 274,052
Percentage 56.5% 16.1%

 
Candidate Albert H. Blumenthal Mario Biaggi
Party Liberal Conservative
Popular vote 262,600 186,977
Percentage 15.4% 11.0%

Results by Borough
  Beame—60–70%
  Beame—50–60%
  Beame—40–50%

Mayor before election

John Lindsay
Liberal

Elected Mayor

Abraham Beame
Democratic

The New York City mayoral election of 1973 occurred on Tuesday, November 6, 1973, with the Democratic candidate, New York City Comptroller Abraham Beame winning the mayoralty with a decisive majority amongst a highly divided field.

Beame, a Democrat, also ran on the Civil Service ballot line.

Beame received a decisive 56.49% of the vote citywide. Beame also swept all five boroughs, breaking 60% of the vote in Brooklyn, winning majorities in Queens and the Bronx, and winning with pluralities in Manhattan and Staten Island.[1]

Beame's distant but closest competitor was the Republican nominee, state senator John Marchi, who received 16.07% of the vote.

Finishing in third was the Liberal Party nominee, Assemblyman Albert H. Blumenthal, who received 15.40%.

Finishing in a distant fourth was the Conservative Party nominee, Congressman Mario Biaggi, who received 10.96%.

Beame defeated his nearest competitor by a landslide 40.42% Democratic margin of victory and was sworn into office in January 1974, replacing outgoing Liberal Party Mayor John Lindsay.

  1. ^ "New York City Mayoral Election 1973". Our Campaigns. Retrieved April 15, 2014.

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