1920 United States presidential election in Rhode Island

1920 United States presidential election in Rhode Island

← 1916 November 2, 1920 1924 →
 
Nominee Warren G. Harding James M. Cox
Party Republican Democratic
Home state Ohio Ohio
Running mate Calvin Coolidge Franklin D. Roosevelt
Electoral vote 5 0
Popular vote 107,463 55,062
Percentage 63.97% 32.78%

County Results
Harding
  60-70%
  70-80%


President before election

Woodrow Wilson
Democratic

Elected President

Warren G. Harding
Republican

The 1920 United States presidential election in Rhode Island took place on November 2, 1920, as part of the 1920 United States presidential election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode Island voted for Republican nominee, Senator Warren G. Harding of Ohio, over the Democratic nominee, Governor James M. Cox of Ohio. Harding ran with Governor Calvin Coolidge of Massachusetts, while Cox ran with Assistant Secretary of the Navy Franklin D. Roosevelt of New York.

Harding won Rhode Island by a margin of 31.19%. His victory in the New England states was helped in by the local popularity of his running mate, Calvin Coolidge, a traditional New England Yankee born in the small-town of Plymouth Notch, Vermont, who had started his political career nearby as Governor of Massachusetts.

As of the 2020 United States presidential election, this is the last time a Republican won over sixty percent of the vote in Rhode Island.


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